I2AB = AB = sqrt((2 - (-3))^2 + (-1 - 2)^2 + (-3 - (-1))^2) = sqrt(5^2 + (-3)^2 + (-2)^2) = sqrt(25 + 9 + 4) = sqrt(38)
CD = sqrt((1 - (-1))^2 + (-4 - 2)^2 + (3 - (-2))^2) = sqrt(2^2 + (-6)^2 + (5)^2) = sqrt(4 + 36 + 25) = sqrt(65)
DI = sqrt((-1 - 1)^2 + (2 - (-4))^2 + (-2 - 3)^2) = sqrt((-2)^2 + (6)^2 + (-5)^2) = sqrt(4 + 36 + 25) = sqrt(65)
Теперь найдем I2AB + 3CDI:
I2AB + 3CDI = sqrt(38) + 3 sqrt(65) ≈ 6.16 + 3 8.06 ≈ 6.16 + 24.18 ≈ 30.34